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A cable that weighs 2lb/ft is used to lift 800 lb of coal up a mineshaft 500 ft deep. Find the work done.
May 30, 2018· Example 2 We have a cable that weighs 2 lbs/ft attached to a bucket filled with coal that weighs 800 lbs. The bucket is initially at the bottom of a 500 ft mine shaft. Answer each of the following about this. Determine the amount of work required to lift the bucket to the midpoint of the shaft.
Sep 08, 2012· A cable that weighs 8 lb/ft is used to lift 800 lb of coal up a mine shaft 550 ft deep. Find the work done. Show how to approximate the required work by a Riemann sum. (Enter xi* as xi.) If somebody could help me out with this, that would be much appreciated. Thank you for all your help in …
Jul 07, 2013· 500ft × 2lb/ft = 1,000 lb. 1,000lb/2 = 500lb (average weight of cable extension) The weight of the cable is averaged because it is presumably. coiling on a spool. Once the cable is on the spool it's weight. is no longer being lifted. If the cable formed a continuous loop, it's weight would not be included at all. 800lb + 500lb = 1,300lb
Nov 03, 2013· The center of gravity of the crane is 10 ft from the pin and the crane weighs physics An initially stationary 15.0-kg crate of cheese wheels is pulled via a cable a distance d= 5.70m up a frictionless ramp to a height of h= 2.50m, where it stops.
Aug 10, 2008· A cable weighs 2 lb/ft is attached to a bucket filled with coal that weighs 800 lbs. The bucket is initially at the bottom of a 500-ft mine shaft. Determine the amount of work required to lift the bucket to a) the midpoint of the shaft, b) from the midpoint to the …
33) Find the work done in winding up a 150-ft cable that weighs 4.00 lb/ft. 33) 34) At lift-off, a rocket weighs 40.2 tons, including the weight of fuel. It is fired vertically, and the fuel is consumed at the rate of 2.95 tons per 1,000 ft of ascent. How much work is done in lifting the rocket to an altitude of 10,000 ft? 34) 35) A construction crane lifts a bucket of sand originally weighing ...
Mar 13, 2015· Since you provided no number, let's say the cable is 2 kg/m. You can fill in your own number in the second equation below. There are two portions to this: Lifting the weight: Force needed is m*g (Newton) and 1J=1Nm so the work is: W_w=m*g*h=150*9.8*50=73500J=73.5kJ Lifting the cable: While lifting the cable, less and less has to be lifted, so the force needed to do this diminishes.
A cable that weighs 6 lb/ft is used to lift 500 lb of coal up a mine shaft 400 ft deep. Find the work done. Show how to approximate the required work by a Riemann sum. (Let x be the distance in feet below the top of the shaft. Enter xi* as xi.)
No problem. I'd raise the panel lift to secure the light, cut wires, unscrew the fixture and lower it with no damage. That one job paid for the lift. What would have been a two man job became a one man job I purchased the optional extension to use for 15 ft. ceilings. This extension also works well.
6.5.11 A cable that weighs 2 lb/ft is used to lift 800 lb of coal up a mineshaft 500 ft deep. Find the work done. First, we ﬁnd the work done on the cable itself. To set up the integral, divide the cable into segments, and for each segment, let x denote its distance from the top of
A cable that weighs 4 lb/ft is used to lift 850 lb of coal up a mine shaft 300 ft deep. Find the work done. Show how to approximate the required work by a Riemann sum. (Let x be the distance in feet below the top of the shaft. Enter x i * as x i .)
21) A rescue cable attached to a helicopter weighs 2 lb/ft. A 160-lb man grabs the end of the rope and is pulled from the ocean into the helicopter. How much work is done in lifting the man if the helicopter is 40 ft above the water? 21) 2
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lbs + lbs/ft * ( depth in (ft) - h) dh How much work is required to lift a 1400-kg satellite to an altitude of 3⋅106 m above the surface of the Earth? The gravitational force is F=GMm/r2, where M is the mass of the Earth, m is the mass of the satellite, and r is the distance between the satellite and the Earth's center.
Feb 06, 2013· A cable that weighs 2 lb/ft is used to lift 800 lb of coal up a mineshaft 500 ft deep.? Find the work done (in ft-lb). Answer Save. 1 Answer. Relevance. bpiguy. Lv 7. 8 years ago. Favorite Answer. I think this can be turned into a calculus problem, but I'm thinking of an easier way. The cable weighs 1000 lbs when fully extended, and the center ...
A cable that weighs 2 lb/ft is used to lift 800 lb of coal up a mine shaft 500 ft deep. Find the work done ... Where k is the linear density of the cable (in lb/ft in this case), y is the distance from the top of the cable, and b is the total distance the weight at the bottom of the cable must travel.
2 · Cable and Chain Work Problems. 13) Find the work done by winding up a hanging cable of length ( 100) ft and weight-density ( 5) lb/ft. 14) For the cable in the preceding exercise, how much work is done to lift the cable ( 50) ft?
A cable that weighs 2 lb/ft is used to lift 800 lb of coal up a mine shaft 500 ft deep. Find the work done. Wcoal = 800(500) ft-lbs = 400,000 ft-lb Wrope = Z 500 0 2(500− y)dy = 2
Feb 06, 2013· A cable that weighs 2 lb/ft is used to lift 800 lb of coal up a mineshaft 500 ft deep.? Find the work done (in ft-lb). Answer Save. 1 Answer. Relevance. bpiguy. Lv 7. 8 years ago. Favourite answer. I think this can be turned into a calculus problem, but I'm thinking of an easier way. The cable weighs 1000 lbs when fully extended, and the center ...
Solved: A cable that weighs 2 lb/ft is used to lift 800 lb of coal up a mine shaft 500 ft deep. Find the work done. - Slader
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2 = 937.5ft-lb+2625ft-lb = 3562.5ft-lb. 2. Move the entire object a small part of the distance. Let's write an expression for the weight (force) on the cable that is hanging down from the winch af-ter y i feet of the cable has been pulled up onto the winch. If y i feet have been pulled up, then 60 −y i feet are still hanging. That part of ...
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A cable that weighs 2 lb/ft is used to lift 300 lb of coal up a mine-shaft 400 ft deep. (a) Find the work needed to lift the cable (only) to the top. (b) Find the work needed to lift the coal (only) to the top. (c) Find the total work required to lift both the cable and the coal to the top.
Jul 15, 2009· A cable that weighs 2 lb/ft is used to lift 800 lb of coal up a mine shaft 500 ft deep. Find the work done. The answer to this problem is: 650,000 ft-lb.
A cable that weighs 2 lbyft is used to lift 800 lb of coal up a mine shaft 500 ft deep. Find the work done. -
A small section of the rope of length dx ft positioned x ft below the top weighs 1 2 dx lb. So the work needed to lift it is dW = 1 2 x dx ft lb. The total work needed to lift the rope is therefore Wrope = ∫ 30 0 1 2 x dx = 225 ft lb: Now for the bucket (without water). Since its weight is constant, the work needed is Wbucket = 30 5 = 150 ft lb:
1.Suppose a 15 foot chain is hanging from a winch 15 feet above the ground. The chain weighs 3 pounds per foot. (a)How much work is required to wind up the entire chain? Answer: The force required to lift an object is equal to the weight of the object. If the bottom of the chain is y feet above the ground, then the length of the chain hanging
10 lb. Split Lead Cable Weight. The 10 lb. Split Lead Cable Weight measures 3 3/4″ wide and 3″ in height . Mounting fasteners included. Separates in the middle and is adjustable to whatever height you want on the cable. The split design gives the ability to tighten the weight to a fixed position on the cable.